(5x^2+29x^2+2x+48)/(x+6)

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Solution for (5x^2+29x^2+2x+48)/(x+6) equation: 


D( x )

x+6 = 0

x+6 = 0

x+6 = 0

x+6 = 0 // - 6

x = -6

x in (-oo:-6) U (-6:+oo)

(5*x^2+29*x^2+2*x+48)/(x+6) = 0

(34*x^2+2*x+48)/(x+6) = 0

34*x^2+2*x+48 = 0

2*(17*x^2+x+24) = 0

17*x^2+x+24 = 0

DELTA = 1^2-(4*17*24)

DELTA = -1631

DELTA < 0

2 = 0

2/(x+6) = 0

x belongs to the empty set

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